5[1-2(2z-1)]=-3(3z-1)+1

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Solution for 5[1-2(2z-1)]=-3(3z-1)+1 equation:


Simplifying
5[1 + -2(2z + -1)] = -3(3z + -1) + 1

Reorder the terms:
5[1 + -2(-1 + 2z)] = -3(3z + -1) + 1
5[1 + (-1 * -2 + 2z * -2)] = -3(3z + -1) + 1
5[1 + (2 + -4z)] = -3(3z + -1) + 1

Combine like terms: 1 + 2 = 3
5[3 + -4z] = -3(3z + -1) + 1
[3 * 5 + -4z * 5] = -3(3z + -1) + 1
[15 + -20z] = -3(3z + -1) + 1

Reorder the terms:
15 + -20z = -3(-1 + 3z) + 1
15 + -20z = (-1 * -3 + 3z * -3) + 1
15 + -20z = (3 + -9z) + 1

Reorder the terms:
15 + -20z = 3 + 1 + -9z

Combine like terms: 3 + 1 = 4
15 + -20z = 4 + -9z

Solving
15 + -20z = 4 + -9z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '9z' to each side of the equation.
15 + -20z + 9z = 4 + -9z + 9z

Combine like terms: -20z + 9z = -11z
15 + -11z = 4 + -9z + 9z

Combine like terms: -9z + 9z = 0
15 + -11z = 4 + 0
15 + -11z = 4

Add '-15' to each side of the equation.
15 + -15 + -11z = 4 + -15

Combine like terms: 15 + -15 = 0
0 + -11z = 4 + -15
-11z = 4 + -15

Combine like terms: 4 + -15 = -11
-11z = -11

Divide each side by '-11'.
z = 1

Simplifying
z = 1

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